Base | Representation |
---|---|
bin | 10110101110100101… |
… | …111010010010010101 |
3 | 2022222202110011102011 |
4 | 112232211322102111 |
5 | 344434411311013 |
6 | 15113330344221 |
7 | 1522516443406 |
oct | 265645722225 |
9 | 68882404364 |
10 | 24404010133 |
11 | a393478018 |
12 | 4890a2b071 |
13 | 23bbc12ca9 |
14 | 12771659ad |
15 | 97c6e7c3d |
hex | 5ae97a495 |
24404010133 has 2 divisors, whose sum is σ = 24404010134. Its totient is φ = 24404010132.
The previous prime is 24404010121. The next prime is 24404010143. The reversal of 24404010133 is 33101040442.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24094179729 + 309830404 = 155223^2 + 17602^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-24404010133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24404010143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12202005066 + 12202005067.
It is an arithmetic number, because the mean of its divisors is an integer number (12202005067).
Almost surely, 224404010133 is an apocalyptic number.
It is an amenable number.
24404010133 is a deficient number, since it is larger than the sum of its proper divisors (1).
24404010133 is an equidigital number, since it uses as much as digits as its factorization.
24404010133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 24404010133 its reverse (33101040442), we get a palindrome (57505050575).
The spelling of 24404010133 in words is "twenty-four billion, four hundred four million, ten thousand, one hundred thirty-three".
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