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2441130343413 = 3813710114471
BaseRepresentation
bin100011100001011110101…
…101001111101111110101
322122100222120102011010020
4203201132231033233311
5304443413331442123
65105234555115353
7341236325361516
oct43413655175765
98570876364106
102441130343413
11861306490a33
12335135742b59
1314927519b008
14862193baa0d
15437757397e3
hex2385eb4fbf5

2441130343413 has 4 divisors (see below), whose sum is σ = 3254840457888. Its totient is φ = 1627420228940.

The previous prime is 2441130343403. The next prime is 2441130343417. The reversal of 2441130343413 is 3143430311442.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2441130343413 - 220 = 2441129294837 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2441130343417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406855057233 + ... + 406855057238.

It is an arithmetic number, because the mean of its divisors is an integer number (813710114472).

Almost surely, 22441130343413 is an apocalyptic number.

It is an amenable number.

2441130343413 is a deficient number, since it is larger than the sum of its proper divisors (813710114475).

2441130343413 is an equidigital number, since it uses as much as digits as its factorization.

2441130343413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 813710114474.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 2441130343413 its reverse (3143430311442), we get a palindrome (5584560654855).

The spelling of 2441130343413 in words is "two trillion, four hundred forty-one billion, one hundred thirty million, three hundred forty-three thousand, four hundred thirteen".

Divisors: 1 3 813710114471 2441130343413