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24414131213317 is a prime number
BaseRepresentation
bin1011000110100010110111…
…00111100101010000000101
310012102222010210002120222201
411203101123213211100011
511200000120042311232
6123531410321154501
75066601634200466
oct543213347452005
9105388123076881
1024414131213317
117862a7a65a79a
1228a375718ba31
13108132027b491
14605916430d6d
152c510313abe7
hex16345b9e5405

24414131213317 has 2 divisors, whose sum is σ = 24414131213318. Its totient is φ = 24414131213316.

The previous prime is 24414131213261. The next prime is 24414131213509. The reversal of 24414131213317 is 71331213141442.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22651041194721 + 1763090018596 = 4759311^2 + 1327814^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24414131213317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24414131211317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12207065606658 + 12207065606659.

It is an arithmetic number, because the mean of its divisors is an integer number (12207065606659).

Almost surely, 224414131213317 is an apocalyptic number.

It is an amenable number.

24414131213317 is a deficient number, since it is larger than the sum of its proper divisors (1).

24414131213317 is an equidigital number, since it uses as much as digits as its factorization.

24414131213317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 37.

Adding to 24414131213317 its reverse (71331213141442), we get a palindrome (95745344354759).

The spelling of 24414131213317 in words is "twenty-four trillion, four hundred fourteen billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred seventeen".