245010113 has 2 divisors, whose sum is σ = 245010114. Its totient is φ = 245010112.

The previous prime is 245010097. The next prime is 245010127. The reversal of 245010113 is 311010542.

245010113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125260864 + 119749249 = 11192^2 + 10943^2 .

It is a cyclic number.

It is not a de Polignac number, because 245010113 - 2⁴ = 245010097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 245010091 and 245010100.

It is not a weakly prime, because it can be changed into another prime (245010413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122505056 + 122505057.

It is an arithmetic number, because the mean of its divisors is an integer number (122505057).

Almost surely, 2^245010113 is an apocalyptic number.

It is an amenable number.

245010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

245010113 is an equidigital number, since it uses as much as digits as its factorization.

245010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 245010113 is about 15652.7988871000. The cubic root of 245010113 is about 625.7410840172.

Adding to 245010113 its reverse (311010542), we get a palindrome (556020655).

The spelling of 245010113 in words is "two hundred forty-five million, ten thousand, one hundred thirteen".