Base | Representation |
---|---|
bin | 100011101001110110000… |
… | …111100100110110011001 |
3 | 22200020011120222020110200 |
4 | 203221312013210312121 |
5 | 310120312420244103 |
6 | 5113322201532413 |
7 | 342005041232430 |
oct | 43516607446631 |
9 | 8606146866420 |
10 | 2450113056153 |
11 | 8650a5a44a74 |
12 | 336a21aa4109 |
13 | 14a0771a7859 |
14 | 8682c3b2117 |
15 | 43aee14e0a3 |
hex | 23a761e4d99 |
2450113056153 has 24 divisors (see below), whose sum is σ = 4044768419328. Its totient is φ = 1400017061952.
The previous prime is 2450113056151. The next prime is 2450113056163. The reversal of 2450113056153 is 3516503110542.
2450113056153 is a `hidden beast` number, since 2 + 4 + 5 + 0 + 1 + 1 + 30 + 5 + 615 + 3 = 666.
It is not a de Polignac number, because 2450113056153 - 21 = 2450113056151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2450113056151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1253400 + ... + 2543862.
It is an arithmetic number, because the mean of its divisors is an integer number (168532017472).
Almost surely, 22450113056153 is an apocalyptic number.
It is an amenable number.
2450113056153 is a deficient number, since it is larger than the sum of its proper divisors (1594655363175).
2450113056153 is a wasteful number, since it uses less digits than its factorization.
2450113056153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1320613 (or 1320610 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
Adding to 2450113056153 its reverse (3516503110542), we get a palindrome (5966616166695).
The spelling of 2450113056153 in words is "two trillion, four hundred fifty billion, one hundred thirteen million, fifty-six thousand, one hundred fifty-three".
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