245025403334111 has 4 divisors (see below), whose sum is σ = 245025865834032. Its totient is φ = 245024940834192.

The previous prime is 245025403334093. The next prime is 245025403334119. The reversal of 245025403334111 is 111433304520542.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-245025403334111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245025403334119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 230454371 + ... + 231515156.

It is an arithmetic number, because the mean of its divisors is an integer number (61256466458508).

Almost surely, 2^{245025403334111} is an apocalyptic number.

245025403334111 is a deficient number, since it is larger than the sum of its proper divisors (462499921).

245025403334111 is an equidigital number, since it uses as much as digits as its factorization.

245025403334111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462499920.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 245025403334111 its reverse (111433304520542), we get a palindrome (356458707854653).

The spelling of 245025403334111 in words is "two hundred forty-five trillion, twenty-five billion, four hundred three million, three hundred thirty-four thousand, one hundred eleven".