Base | Representation |
---|---|
bin | 110111101101110011100100… |
… | …101001000001010101110011 |
3 | 1012010121121212112021222020011 |
4 | 313231303210221001111303 |
5 | 224104220023343130120 |
6 | 2225053544152155351 |
7 | 102420402213524500 |
oct | 6755634451012563 |
9 | 1163547775258204 |
10 | 245040310130035 |
11 | 71094014976232 |
12 | 23596554098b57 |
13 | a696282006a44 |
14 | 447202b3024a7 |
15 | 1d4e0da324c5a |
hex | dedce4a41573 |
245040310130035 has 24 divisors (see below), whose sum is σ = 342120411034416. Its totient is φ = 167996133184320.
The previous prime is 245040310130029. The next prime is 245040310130053. The reversal of 245040310130035 is 530031013040542.
It is not a de Polignac number, because 245040310130035 - 25 = 245040310130003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 245040310129979 and 245040310130006.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 92464701 + ... + 95077870.
It is an arithmetic number, because the mean of its divisors is an integer number (14255017126434).
Almost surely, 2245040310130035 is an apocalyptic number.
245040310130035 is a deficient number, since it is larger than the sum of its proper divisors (97080100904381).
245040310130035 is a wasteful number, since it uses less digits than its factorization.
245040310130035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187547923 (or 187547916 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 245040310130035 its reverse (530031013040542), we get a palindrome (775071323170577).
The spelling of 245040310130035 in words is "two hundred forty-five trillion, forty billion, three hundred ten million, one hundred thirty thousand, thirty-five".
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