Base | Representation |
---|---|
bin | 110111101101110100011111… |
… | …101001100111000001110111 |
3 | 1012010121201102112011200210111 |
4 | 313231310133221213001313 |
5 | 224104224040313441101 |
6 | 2225054230315403451 |
7 | 102420435564500404 |
oct | 6755643751470167 |
9 | 1163551375150714 |
10 | 245041300140151 |
11 | 71094482796509 |
12 | 2359678b753587 |
13 | a6963ac156b48 |
14 | 44720c29ad2ab |
15 | 1d4e1471d1251 |
hex | dedd1fa67077 |
245041300140151 has 16 divisors (see below), whose sum is σ = 254091391948800. Its totient is φ = 236167080353568.
The previous prime is 245041300140101. The next prime is 245041300140223. The reversal of 245041300140151 is 151041003140542.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-245041300140151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245041300140101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85658080 + ... + 88472533.
It is an arithmetic number, because the mean of its divisors is an integer number (15880711996800).
Almost surely, 2245041300140151 is an apocalyptic number.
245041300140151 is a deficient number, since it is larger than the sum of its proper divisors (9050091808649).
245041300140151 is a wasteful number, since it uses less digits than its factorization.
245041300140151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174131118.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 245041300140151 its reverse (151041003140542), we get a palindrome (396082303280693).
The spelling of 245041300140151 in words is "two hundred forty-five trillion, forty-one billion, three hundred million, one hundred forty thousand, one hundred fifty-one".
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