Search a number
-
+
245041300140223 is a prime number
BaseRepresentation
bin110111101101110100011111…
…101001100111000010111111
31012010121201102112011200220011
4313231310133221213002333
5224104224040313441343
62225054230315404051
7102420435564500536
oct6755643751470277
91163551375150804
10245041300140223
1171094482796574
122359678b753627
13a6963ac156ba2
1444720c29ad31d
151d4e1471d129d
hexdedd1fa670bf

245041300140223 has 2 divisors, whose sum is σ = 245041300140224. Its totient is φ = 245041300140222.

The previous prime is 245041300140101. The next prime is 245041300140251. The reversal of 245041300140223 is 322041003140542.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-245041300140223 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (245041300170223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122520650070111 + 122520650070112.

It is an arithmetic number, because the mean of its divisors is an integer number (122520650070112).

Almost surely, 2245041300140223 is an apocalyptic number.

245041300140223 is a deficient number, since it is larger than the sum of its proper divisors (1).

245041300140223 is an equidigital number, since it uses as much as digits as its factorization.

245041300140223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 245041300140223 its reverse (322041003140542), we get a palindrome (567082303280765).

The spelling of 245041300140223 in words is "two hundred forty-five trillion, forty-one billion, three hundred million, one hundred forty thousand, two hundred twenty-three".