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245131552103 = 1912901660637
BaseRepresentation
bin1110010001001011111…
…0101010010101100111
3212102201122021002010012
43210102332222111213
513004012134131403
6304340055520435
723465405546054
oct3442276522547
9772648232105
10245131552103
1194a61409299
123b61208911b
131a1675703a9
14bc15dd602b
15659a6eaed8
hex3912faa567

245131552103 has 4 divisors (see below), whose sum is σ = 258033212760. Its totient is φ = 232229891448.

The previous prime is 245131552033. The next prime is 245131552129. The reversal of 245131552103 is 301255131542.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 245131552103 - 222 = 245127357799 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 245131552103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245131552163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6450830300 + ... + 6450830337.

It is an arithmetic number, because the mean of its divisors is an integer number (64508303190).

Almost surely, 2245131552103 is an apocalyptic number.

245131552103 is a deficient number, since it is larger than the sum of its proper divisors (12901660657).

245131552103 is a wasteful number, since it uses less digits than its factorization.

245131552103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12901660656.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 245131552103 its reverse (301255131542), we get a palindrome (546386683645).

The spelling of 245131552103 in words is "two hundred forty-five billion, one hundred thirty-one million, five hundred fifty-two thousand, one hundred three".

Divisors: 1 19 12901660637 245131552103