Base | Representation |
---|---|
bin | 1110010001010001001… |
… | …0100101001011111111 |
3 | 212102210011122202001222 |
4 | 3210110102211023333 |
5 | 13004033302113403 |
6 | 304342203223555 |
7 | 23466063542066 |
oct | 3442422451377 |
9 | 772704582058 |
10 | 245153551103 |
11 | 94a7287448a |
12 | 3b619517bbb |
13 | 1a16bca3656 |
14 | bc18cc11dd |
15 | 659c5e4338 |
hex | 39144a52ff |
245153551103 has 2 divisors, whose sum is σ = 245153551104. Its totient is φ = 245153551102.
The previous prime is 245153551099. The next prime is 245153551147. The reversal of 245153551103 is 301155351542.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245153551103 - 22 = 245153551099 is a prime.
It is a super-3 number, since 3×2451535511033 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (245153551163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122576775551 + 122576775552.
It is an arithmetic number, because the mean of its divisors is an integer number (122576775552).
Almost surely, 2245153551103 is an apocalyptic number.
245153551103 is a deficient number, since it is larger than the sum of its proper divisors (1).
245153551103 is an equidigital number, since it uses as much as digits as its factorization.
245153551103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 245153551103 in words is "two hundred forty-five billion, one hundred fifty-three million, five hundred fifty-one thousand, one hundred three".
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