Base | Representation |
---|---|
bin | 100011101011100111010… |
… | …001010100010000000101 |
3 | 22200102001220002212200211 |
4 | 203223213101110100011 |
5 | 310133204411410023 |
6 | 5114234414435421 |
7 | 342103062210610 |
oct | 43534721242005 |
9 | 8612056085624 |
10 | 2452011435013 |
11 | 86598a593118 |
12 | 337271802b71 |
13 | 14a2ba59155a |
14 | 8696c577177 |
15 | 43bb0b3ba0d |
hex | 23ae7454405 |
2452011435013 has 4 divisors (see below), whose sum is σ = 2802298782880. Its totient is φ = 2101724087148.
The previous prime is 2452011435001. The next prime is 2452011435023. The reversal of 2452011435013 is 3105341102542.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 2452011435013 - 25 = 2452011434981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2452011435023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175143673923 + ... + 175143673936.
It is an arithmetic number, because the mean of its divisors is an integer number (700574695720).
Almost surely, 22452011435013 is an apocalyptic number.
It is an amenable number.
2452011435013 is a deficient number, since it is larger than the sum of its proper divisors (350287347867).
2452011435013 is an equidigital number, since it uses as much as digits as its factorization.
2452011435013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350287347866.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 2452011435013 its reverse (3105341102542), we get a palindrome (5557352537555).
The spelling of 2452011435013 in words is "two trillion, four hundred fifty-two billion, eleven million, four hundred thirty-five thousand, thirteen".
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