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245402252112181 is a prime number
BaseRepresentation
bin110111110011000100101010…
…000100000111000100110101
31012011220020002212222201102011
4313303010222010013010311
5224131132303020042211
62225532123245044221
7102455504401566313
oct6763045204070465
91164806085881364
10245402252112181
117121356876a50a
1223634725856671
13a6c1443a05198
144485764bad0b3
151d58720988921
hexdf312a107135

245402252112181 has 2 divisors, whose sum is σ = 245402252112182. Its totient is φ = 245402252112180.

The previous prime is 245402252112109. The next prime is 245402252112197. The reversal of 245402252112181 is 181211252204542.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 222817269514225 + 22584982597956 = 14927065^2 + 4752366^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-245402252112181 is a prime.

It is a super-2 number, since 2×2454022521121812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (245402252152181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122701126056090 + 122701126056091.

It is an arithmetic number, because the mean of its divisors is an integer number (122701126056091).

Almost surely, 2245402252112181 is an apocalyptic number.

It is an amenable number.

245402252112181 is a deficient number, since it is larger than the sum of its proper divisors (1).

245402252112181 is an equidigital number, since it uses as much as digits as its factorization.

245402252112181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 102400, while the sum is 40.

The spelling of 245402252112181 in words is "two hundred forty-five trillion, four hundred two billion, two hundred fifty-two million, one hundred twelve thousand, one hundred eighty-one".