Base | Representation |
---|---|
bin | 1110010010010110000… |
… | …1000010110011111011 |
3 | 212110112022110200001212 |
4 | 3210211201002303323 |
5 | 13010131243231011 |
6 | 304431005433335 |
7 | 23506203203324 |
oct | 3444541026373 |
9 | 773468420055 |
10 | 245442555131 |
11 | 95100a18494 |
12 | 3b69a26b84b |
13 | 1a1b6b21457 |
14 | bc4543144b |
15 | 65b7b8008b |
hex | 3925842cfb |
245442555131 has 2 divisors, whose sum is σ = 245442555132. Its totient is φ = 245442555130.
The previous prime is 245442555109. The next prime is 245442555181. The reversal of 245442555131 is 131555244542.
It is a happy number.
245442555131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245442555131 - 234 = 228262685947 is a prime.
It is a super-2 number, since 2×2454425551312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (245442555101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122721277565 + 122721277566.
It is an arithmetic number, because the mean of its divisors is an integer number (122721277566).
Almost surely, 2245442555131 is an apocalyptic number.
245442555131 is a deficient number, since it is larger than the sum of its proper divisors (1).
245442555131 is an equidigital number, since it uses as much as digits as its factorization.
245442555131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 480000, while the sum is 41.
Adding to 245442555131 its reverse (131555244542), we get a palindrome (376997799673).
The spelling of 245442555131 in words is "two hundred forty-five billion, four hundred forty-two million, five hundred fifty-five thousand, one hundred thirty-one".
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