2455040340031 has 4 divisors (see below), whose sum is σ = 2455044179464. Its totient is φ = 2455036500600.

The previous prime is 2455040340013. The next prime is 2455040340059. The reversal of 2455040340031 is 1300430405542.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2455040340031 - 2²⁵ = 2455006785599 is a prime.

It is a super-3 number, since 3×2455040340031³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2455040339975 and 2455040340002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2455040340631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 703905 + ... + 2324986.

It is an arithmetic number, because the mean of its divisors is an integer number (613761044866).

Almost surely, 2^{2455040340031} is an apocalyptic number.

2455040340031 is a deficient number, since it is larger than the sum of its proper divisors (3839433).

2455040340031 is an equidigital number, since it uses as much as digits as its factorization.

2455040340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3839432.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 2455040340031 its reverse (1300430405542), we get a palindrome (3755470745573).

The spelling of 2455040340031 in words is "two trillion, four hundred fifty-five billion, forty million, three hundred forty thousand, thirty-one".