Base | Representation |
---|---|
bin | 1110011000001101010… |
… | …0101111001000101001 |
3 | 212121120222220121200021 |
4 | 3212003110233020221 |
5 | 13021342143341423 |
6 | 305251110240441 |
7 | 23563203434626 |
oct | 3460324571051 |
9 | 777528817607 |
10 | 247016387113 |
11 | 95839346781 |
12 | 3ba59356121 |
13 | 1a3a7bc4492 |
14 | bd5447334d |
15 | 665ae1095d |
hex | 398352f229 |
247016387113 has 2 divisors, whose sum is σ = 247016387114. Its totient is φ = 247016387112.
The previous prime is 247016387017. The next prime is 247016387119. The reversal of 247016387113 is 311783610742.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135986150169 + 111030236944 = 368763^2 + 333212^2 .
It is a cyclic number.
It is not a de Polignac number, because 247016387113 - 217 = 247016256041 is a prime.
It is a super-2 number, since 2×2470163871132 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 247016387113.
It is not a weakly prime, because it can be changed into another prime (247016387119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 123508193556 + 123508193557.
It is an arithmetic number, because the mean of its divisors is an integer number (123508193557).
Almost surely, 2247016387113 is an apocalyptic number.
It is an amenable number.
247016387113 is a deficient number, since it is larger than the sum of its proper divisors (1).
247016387113 is an equidigital number, since it uses as much as digits as its factorization.
247016387113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 169344, while the sum is 43.
Adding to 247016387113 its reverse (311783610742), we get a palindrome (558799997855).
The spelling of 247016387113 in words is "two hundred forty-seven billion, sixteen million, three hundred eighty-seven thousand, one hundred thirteen".
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