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2482599390613 is a prime number
BaseRepresentation
bin100100001000000110011…
…101000110110110010101
322210100000121202000112021
4210020012131012312111
5311133330420444423
65140253532453141
7344235061432666
oct44100635066625
98710017660467
102482599390613
118779566a8971
1234118961a1b1
131501536c5c74
1488230b1136d
15448a11a495d
hex24206746d95

2482599390613 has 2 divisors, whose sum is σ = 2482599390614. Its totient is φ = 2482599390612.

The previous prime is 2482599390587. The next prime is 2482599390619. The reversal of 2482599390613 is 3160939952842.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2454179162724 + 28420227889 = 1566582^2 + 168583^2 .

It is a cyclic number.

It is not a de Polignac number, because 2482599390613 - 213 = 2482599382421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2482599390619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1241299695306 + 1241299695307.

It is an arithmetic number, because the mean of its divisors is an integer number (1241299695307).

Almost surely, 22482599390613 is an apocalyptic number.

It is an amenable number.

2482599390613 is a deficient number, since it is larger than the sum of its proper divisors (1).

2482599390613 is an equidigital number, since it uses as much as digits as its factorization.

2482599390613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25194240, while the sum is 61.

The spelling of 2482599390613 in words is "two trillion, four hundred eighty-two billion, five hundred ninety-nine million, three hundred ninety thousand, six hundred thirteen".