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2491331942 = 211293904909
BaseRepresentation
bin1001010001111110…
…1011010101100110
320102121212202221102
42110133223111212
520100240110232
61051113520102
7115510654301
oct22437532546
96377782842
102491331942
111069323620
12596413032
133091b5c18
14198c35b38
15e8ab7662
hex947eb566

2491331942 has 16 divisors (see below), whose sum is σ = 4217302800. Its totient is φ = 1093374240.

The previous prime is 2491331923. The next prime is 2491331959.

2491331942 is nontrivially palindromic in base 10.

It is a super-3 number, since 3×24913319423 (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2491331896 and 2491331905.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1951817 + ... + 1953092.

It is an arithmetic number, because the mean of its divisors is an integer number (263581425).

Almost surely, 22491331942 is an apocalyptic number.

2491331942 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

2491331942 is a deficient number, since it is larger than the sum of its proper divisors (1725970858).

2491331942 is a wasteful number, since it uses less digits than its factorization.

2491331942 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3904951.

The product of its digits is 46656, while the sum is 38.

The square root of 2491331942 is about 49913.2441542323. The cubic root of 2491331942 is about 1355.6384099670.

It can be divided in two parts, 2491 and 331942, that added together give a palindrome (334433).

The spelling of 2491331942 in words is "two billion, four hundred ninety-one million, three hundred thirty-one thousand, nine hundred forty-two".

Divisors: 1 2 11 22 29 58 319 638 3904909 7809818 42953999 85907998 113242361 226484722 1245665971 2491331942