249388000051 has 2 divisors, whose sum is σ = 249388000052. Its totient is φ = 249388000050.

The previous prime is 249387999997. The next prime is 249388000139. The reversal of 249388000051 is 150000883942.

249388000051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 249388000051 - 2⁷ = 249387999923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 249387999968 and 249388000013.

It is not a weakly prime, because it can be changed into another prime (249388000451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124694000025 + 124694000026.

It is an arithmetic number, because the mean of its divisors is an integer number (124694000026).

Almost surely, 2^249388000051 is an apocalyptic number.

249388000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

249388000051 is an equidigital number, since it uses as much as digits as its factorization.

249388000051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 40.

Adding to 249388000051 its reverse (150000883942), we get a palindrome (399388883993).

The spelling of 249388000051 in words is "two hundred forty-nine billion, three hundred eighty-eight million, fifty-one", and thus it is an aban number.