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249388000013 = 715134874563
BaseRepresentation
bin1110100001000010101…
…1101110001100001101
3212211201021112000222002
43220100223232030031
513041221312000023
6310322310202045
724006032011145
oct3502053561415
9784637460862
10249388000013
119684602a639
12403bb653325
131a695351319
14c0db423925
15674922ab28
hex3a10aee30d

249388000013 has 4 divisors (see below), whose sum is σ = 249422881728. Its totient is φ = 249353118300.

The previous prime is 249387999997. The next prime is 249388000051. The reversal of 249388000013 is 310000883942.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 249388000013 - 24 = 249387999997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (249388002013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17430131 + ... + 17444432.

It is an arithmetic number, because the mean of its divisors is an integer number (62355720432).

Almost surely, 2249388000013 is an apocalyptic number.

It is an amenable number.

249388000013 is a deficient number, since it is larger than the sum of its proper divisors (34881715).

249388000013 is an equidigital number, since it uses as much as digits as its factorization.

249388000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34881714.

The product of its (nonzero) digits is 41472, while the sum is 38.

Adding to 249388000013 its reverse (310000883942), we get a palindrome (559388883955).

The spelling of 249388000013 in words is "two hundred forty-nine billion, three hundred eighty-eight million, thirteen", and thus it is an aban number.

Divisors: 1 7151 34874563 249388000013