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2498000413 is a prime number
BaseRepresentation
bin1001010011100100…
…0111011000011101
320110002102120100211
42110321013120131
520103442003123
61051512452421
7115621440016
oct22471073035
96402376324
102498000413
111072068757
125986aa111
1330a6ac26c
14199a9000d
15e948340d
hex94e4761d

2498000413 has 2 divisors, whose sum is σ = 2498000414. Its totient is φ = 2498000412.

The previous prime is 2498000369. The next prime is 2498000431. The reversal of 2498000413 is 3140008942.

2498000413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (2498000431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2331151524 + 166848889 = 48282^2 + 12917^2 .

It is a cyclic number.

It is not a de Polignac number, because 2498000413 - 225 = 2464445981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2498000473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1249000206 + 1249000207.

It is an arithmetic number, because the mean of its divisors is an integer number (1249000207).

Almost surely, 22498000413 is an apocalyptic number.

It is an amenable number.

2498000413 is a deficient number, since it is larger than the sum of its proper divisors (1).

2498000413 is an equidigital number, since it uses as much as digits as its factorization.

2498000413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

The square root of 2498000413 is about 49980.0001300520. Note that the first 3 decimals coincide. The cubic root of 2498000413 is about 1356.8468641699.

The spelling of 2498000413 in words is "two billion, four hundred ninety-eight million, four hundred thirteen", and thus it is an aban number.