2500000033 has 2 divisors, whose sum is σ = 2500000034. Its totient is φ = 2500000032.

The previous prime is 2500000001. The next prime is 2500000039. The reversal of 2500000033 is 3300000052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2193329889 + 306670144 = 46833^2 + 17512^2 .

It is a cyclic number.

It is not a de Polignac number, because 2500000033 - 2⁵ = 2500000001 is a prime.

2500000033 is a modest number, since divided by 33 gives 25 as remainder.

It is a junction number, because it is equal to n+sod(n) for n = 2499999959 and 2500000022.

It is not a weakly prime, because it can be changed into another prime (2500000039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250000016 + 1250000017.

It is an arithmetic number, because the mean of its divisors is an integer number (1250000017).

Almost surely, 2^2500000033 is an apocalyptic number.

It is an amenable number.

2500000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

2500000033 is an equidigital number, since it uses as much as digits as its factorization.

2500000033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 13.

The square root of 2500000033 is about 50000.0003300000. Note that the first 3 decimals coincide. The cubic root of 2500000033 is about 1357.2088142692.

Adding to 2500000033 its reverse (3300000052), we get a palindrome (5800000085).

The spelling of 2500000033 in words is "two billion, five hundred million, thirty-three", and thus it is an aban number.