Base | Representation |
---|---|
bin | 10111010010001001… |
… | …010111000011010001 |
3 | 2101112022212021022010 |
4 | 113102021113003101 |
5 | 402200112134203 |
6 | 15252435333133 |
7 | 1543351535202 |
oct | 272211270321 |
9 | 71468767263 |
10 | 25000505553 |
11 | a66a151941 |
12 | 4a187511a9 |
13 | 248568266a |
14 | 12d24795a9 |
15 | 9b4c72303 |
hex | 5d22570d1 |
25000505553 has 4 divisors (see below), whose sum is σ = 33334007408. Its totient is φ = 16667003700.
The previous prime is 25000505521. The next prime is 25000505557. The reversal of 25000505553 is 35550500052.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 25000505553 - 25 = 25000505521 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 25000505553.
It is not an unprimeable number, because it can be changed into a prime (25000505557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4166750923 + ... + 4166750928.
It is an arithmetic number, because the mean of its divisors is an integer number (8333501852).
Almost surely, 225000505553 is an apocalyptic number.
It is an amenable number.
25000505553 is a deficient number, since it is larger than the sum of its proper divisors (8333501855).
25000505553 is an equidigital number, since it uses as much as digits as its factorization.
25000505553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8333501854.
The product of its (nonzero) digits is 18750, while the sum is 30.
The spelling of 25000505553 in words is "twenty-five billion, five hundred five thousand, five hundred fifty-three".
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