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25000505553 = 38333501851
BaseRepresentation
bin10111010010001001…
…010111000011010001
32101112022212021022010
4113102021113003101
5402200112134203
615252435333133
71543351535202
oct272211270321
971468767263
1025000505553
11a66a151941
124a187511a9
13248568266a
1412d24795a9
159b4c72303
hex5d22570d1

25000505553 has 4 divisors (see below), whose sum is σ = 33334007408. Its totient is φ = 16667003700.

The previous prime is 25000505521. The next prime is 25000505557. The reversal of 25000505553 is 35550500052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 25000505553 - 25 = 25000505521 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 25000505553.

It is not an unprimeable number, because it can be changed into a prime (25000505557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4166750923 + ... + 4166750928.

It is an arithmetic number, because the mean of its divisors is an integer number (8333501852).

Almost surely, 225000505553 is an apocalyptic number.

It is an amenable number.

25000505553 is a deficient number, since it is larger than the sum of its proper divisors (8333501855).

25000505553 is an equidigital number, since it uses as much as digits as its factorization.

25000505553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8333501854.

The product of its (nonzero) digits is 18750, while the sum is 30.

The spelling of 25000505553 in words is "twenty-five billion, five hundred five thousand, five hundred fifty-three".

Divisors: 1 3 8333501851 25000505553