25001014141 has 4 divisors (see below), whose sum is σ = 25001469792. Its totient is φ = 25000558492.

The previous prime is 25001014127. The next prime is 25001014193. The reversal of 25001014141 is 14141010052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25001014141 - 2¹¹ = 25001012093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25001014541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132121 + ... + 259726.

It is an arithmetic number, because the mean of its divisors is an integer number (6250367448).

Almost surely, 2^25001014141 is an apocalyptic number.

It is an amenable number.

25001014141 is a deficient number, since it is larger than the sum of its proper divisors (455651).

25001014141 is an equidigital number, since it uses as much as digits as its factorization.

25001014141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 455650.

The product of its (nonzero) digits is 160, while the sum is 19.

Adding to 25001014141 its reverse (14141010052), we get a palindrome (39142024193).

The spelling of 25001014141 in words is "twenty-five billion, one million, fourteen thousand, one hundred forty-one".