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2500126275139 is a prime number
BaseRepresentation
bin100100011000011011001…
…000110111011001000011
322212000021002200000010121
4210120123020313121003
5311430224311301024
65152313034441111
7345425313462463
oct44303310673103
98760232600117
102500126275139
118843301166a9
1234465b293197
131519b78c535c
1489014783ba3
1545079c558e4
hex2461b237643

2500126275139 has 2 divisors, whose sum is σ = 2500126275140. Its totient is φ = 2500126275138.

The previous prime is 2500126275107. The next prime is 2500126275187. The reversal of 2500126275139 is 9315726210052.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2500126275139 - 25 = 2500126275107 is a prime.

It is a super-3 number, since 3×25001262751393 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2500126275095 and 2500126275104.

It is not a weakly prime, because it can be changed into another prime (2500126275539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250063137569 + 1250063137570.

It is an arithmetic number, because the mean of its divisors is an integer number (1250063137570).

Almost surely, 22500126275139 is an apocalyptic number.

2500126275139 is a deficient number, since it is larger than the sum of its proper divisors (1).

2500126275139 is an equidigital number, since it uses as much as digits as its factorization.

2500126275139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 2500126275139 in words is "two trillion, five hundred billion, one hundred twenty-six million, two hundred seventy-five thousand, one hundred thirty-nine".