Base | Representation |
---|---|
bin | 111000110110001011001110… |
… | …100110101010010011100101 |
3 | 1012210020001120120000112211001 |
4 | 320312023032212222103211 |
5 | 230232210133202311123 |
6 | 2243422342211313301 |
7 | 103442610623533255 |
oct | 7066131646522345 |
9 | 1183201516015731 |
10 | 250013512541413 |
11 | 72731153a99835 |
12 | 2405a3635ab831 |
13 | a96723330a19a |
14 | 45a4a0ba95965 |
15 | 1dd865a1450ad |
hex | e362ce9aa4e5 |
250013512541413 has 2 divisors, whose sum is σ = 250013512541414. Its totient is φ = 250013512541412.
The previous prime is 250013512541383. The next prime is 250013512541449. The reversal of 250013512541413 is 314145215310052.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 195567442918849 + 54446069622564 = 13984543^2 + 7378758^2 .
It is a cyclic number.
It is not a de Polignac number, because 250013512541413 - 213 = 250013512533221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (250013512541213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125006756270706 + 125006756270707.
It is an arithmetic number, because the mean of its divisors is an integer number (125006756270707).
Almost surely, 2250013512541413 is an apocalyptic number.
It is an amenable number.
250013512541413 is a deficient number, since it is larger than the sum of its proper divisors (1).
250013512541413 is an equidigital number, since it uses as much as digits as its factorization.
250013512541413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 250013512541413 its reverse (314145215310052), we get a palindrome (564158727851465).
The spelling of 250013512541413 in words is "two hundred fifty trillion, thirteen billion, five hundred twelve million, five hundred forty-one thousand, four hundred thirteen".
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