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2500140265297 is a prime number
BaseRepresentation
bin100100011000011011111…
…110001110111101010001
322212000022001222210000121
4210120123332032331101
5311430241401442142
65152314254350241
7345425543421223
oct44303376167521
98760261883017
102500140265297
11884338001714
12344663abb381
131519ba78315c
1489016586413
154507b0bac67
hex2461bf8ef51

2500140265297 has 2 divisors, whose sum is σ = 2500140265298. Its totient is φ = 2500140265296.

The previous prime is 2500140265243. The next prime is 2500140265303. The reversal of 2500140265297 is 7925620410052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2500070107921 + 70157376 = 1581161^2 + 8376^2 .

It is a cyclic number.

It is not a de Polignac number, because 2500140265297 - 215 = 2500140232529 is a prime.

It is a super-3 number, since 3×25001402652973 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2500140265397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250070132648 + 1250070132649.

It is an arithmetic number, because the mean of its divisors is an integer number (1250070132649).

Almost surely, 22500140265297 is an apocalyptic number.

It is an amenable number.

2500140265297 is a deficient number, since it is larger than the sum of its proper divisors (1).

2500140265297 is an equidigital number, since it uses as much as digits as its factorization.

2500140265297 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 2500140265297 in words is "two trillion, five hundred billion, one hundred forty million, two hundred sixty-five thousand, two hundred ninety-seven".