Base | Representation |
---|---|
bin | 100100011000011111110… |
… | …110011101001001100101 |
3 | 22212000110121102200001211 |
4 | 210120133312131021211 |
5 | 311430410031211031 |
6 | 5152324541151421 |
7 | 345430263462223 |
oct | 44303766351145 |
9 | 8760417380054 |
10 | 2500205335141 |
11 | 884370805648 |
12 | 34468185b571 |
13 | 1519cb0b6917 |
14 | 89021083b13 |
15 | 45081b70bb1 |
hex | 2461fd9d265 |
2500205335141 has 4 divisors (see below), whose sum is σ = 2500257133612. Its totient is φ = 2500153536672.
The previous prime is 2500205335129. The next prime is 2500205335151. The reversal of 2500205335141 is 1415335020052.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 460104456100 + 2040100879041 = 678310^2 + 1428321^2 .
It is a cyclic number.
It is not a de Polignac number, because 2500205335141 - 25 = 2500205335109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2500205335151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25826766 + ... + 25923391.
It is an arithmetic number, because the mean of its divisors is an integer number (625064283403).
Almost surely, 22500205335141 is an apocalyptic number.
It is an amenable number.
2500205335141 is a deficient number, since it is larger than the sum of its proper divisors (51798471).
2500205335141 is an equidigital number, since it uses as much as digits as its factorization.
2500205335141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51798470.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 2500205335141 in words is "two trillion, five hundred billion, two hundred five million, three hundred thirty-five thousand, one hundred forty-one".
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