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250025552013421 is a prime number
BaseRepresentation
bin111000110110010110011100…
…001101100110100001101101
31012210021012122121102002120201
4320312112130031212201231
5230232404312303412141
62243432053011113501
7103443515154415612
oct7066263415464155
91183235577362521
10250025552013421
1172736271a602a8
12240607635a2891
13a9684016b2112
1445a5430a2a509
151dd8b120b1031
hexe3659c36686d

250025552013421 has 2 divisors, whose sum is σ = 250025552013422. Its totient is φ = 250025552013420.

The previous prime is 250025552013379. The next prime is 250025552013427. The reversal of 250025552013421 is 124310255520052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 230068648704196 + 19956903309225 = 15168014^2 + 4467315^2 .

It is a cyclic number.

It is not a de Polignac number, because 250025552013421 - 29 = 250025552012909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250025552013427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125012776006710 + 125012776006711.

It is an arithmetic number, because the mean of its divisors is an integer number (125012776006711).

Almost surely, 2250025552013421 is an apocalyptic number.

It is an amenable number.

250025552013421 is a deficient number, since it is larger than the sum of its proper divisors (1).

250025552013421 is an equidigital number, since it uses as much as digits as its factorization.

250025552013421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120000, while the sum is 37.

The spelling of 250025552013421 in words is "two hundred fifty trillion, twenty-five billion, five hundred fifty-two million, thirteen thousand, four hundred twenty-one".