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250030512421423 is a prime number
BaseRepresentation
bin111000110110011011000011…
…111000000011101000101111
31012210021200110022021221010121
4320312123003320003220233
5230232444442134441143
62243434233125545411
7103444052116244536
oct7066330370035057
91183250408257117
10250030512421423
1172738387a86248
1224061708875267
13a968a1228aa96
1445a578174331d
151dd8d027e67ed
hexe366c3e03a2f

250030512421423 has 2 divisors, whose sum is σ = 250030512421424. Its totient is φ = 250030512421422.

The previous prime is 250030512421411. The next prime is 250030512421433. The reversal of 250030512421423 is 324124215030052.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250030512421423 is a prime.

It is a super-2 number, since 2×2500305124214232 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250030512421433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125015256210711 + 125015256210712.

It is an arithmetic number, because the mean of its divisors is an integer number (125015256210712).

Almost surely, 2250030512421423 is an apocalyptic number.

250030512421423 is a deficient number, since it is larger than the sum of its proper divisors (1).

250030512421423 is an equidigital number, since it uses as much as digits as its factorization.

250030512421423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 250030512421423 its reverse (324124215030052), we get a palindrome (574154727451475).

The spelling of 250030512421423 in words is "two hundred fifty trillion, thirty billion, five hundred twelve million, four hundred twenty-one thousand, four hundred twenty-three".