Base | Representation |
---|---|
bin | 111000110110011100111011… |
… | …101000001111101011000110 |
3 | 1012210021212122022210211220111 |
4 | 320312130323220033223012 |
5 | 230233013101003323332 |
6 | 2243435204340223234 |
7 | 103444152653425120 |
oct | 7066347350175306 |
9 | 1183255568724814 |
10 | 250032521542342 |
11 | 72739219092560 |
12 | 24061b8969ab1a |
13 | a968c725a9826 |
14 | 45a58d24d4210 |
15 | 1dd8dbddab947 |
hex | e3673ba0fac6 |
250032521542342 has 32 divisors (see below), whose sum is σ = 468895775408640. Its totient is φ = 97143916390080.
The previous prime is 250032521542327. The next prime is 250032521542361. The reversal of 250032521542342 is 243245125230052.
It is a junction number, because it is equal to n+sod(n) for n = 250032521542295 and 250032521542304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2261209063 + ... + 2261319634.
It is an arithmetic number, because the mean of its divisors is an integer number (14652992981520).
Almost surely, 2250032521542342 is an apocalyptic number.
250032521542342 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
250032521542342 is a deficient number, since it is larger than the sum of its proper divisors (218863253866298).
250032521542342 is a wasteful number, since it uses less digits than its factorization.
250032521542342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4522529076.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 250032521542342 its reverse (243245125230052), we get a palindrome (493277646772394).
The spelling of 250032521542342 in words is "two hundred fifty trillion, thirty-two billion, five hundred twenty-one million, five hundred forty-two thousand, three hundred forty-two".
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