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2500351323 = 3833450441
BaseRepresentation
bin1001010100001000…
…0101010101011011
320110020212000012120
42111002011111123
520110042220243
61052035112323
7115650431001
oct22502052533
96406760176
102500351323
111073423a58
125994426a3
1330b023332
1419a102a71
15e9799c83
hex9508555b

2500351323 has 4 divisors (see below), whose sum is σ = 3333801768. Its totient is φ = 1666900880.

The previous prime is 2500351291. The next prime is 2500351351. The reversal of 2500351323 is 3231530052.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2500351323 - 25 = 2500351291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2500351293 and 2500351302.

It is not an unprimeable number, because it can be changed into a prime (2500351363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416725218 + ... + 416725223.

It is an arithmetic number, because the mean of its divisors is an integer number (833450442).

Almost surely, 22500351323 is an apocalyptic number.

2500351323 is a deficient number, since it is larger than the sum of its proper divisors (833450445).

2500351323 is an equidigital number, since it uses as much as digits as its factorization.

2500351323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 833450444.

The product of its (nonzero) digits is 2700, while the sum is 24.

The square root of 2500351323 is about 50003.5131065808. The cubic root of 2500351323 is about 1357.2723811423.

Adding to 2500351323 its reverse (3231530052), we get a palindrome (5731881375).

The spelling of 2500351323 in words is "two billion, five hundred million, three hundred fifty-one thousand, three hundred twenty-three".

Divisors: 1 3 833450441 2500351323