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250040135404361 is a prime number
BaseRepresentation
bin111000110110100100000001…
…011100110100101101001001
31012210022121021221122010002002
4320312210001130310231021
5230233124144130414421
62243442504043520345
7103444542435246431
oct7066440134645511
91183277257563062
10250040135404361
11727414759a2805
12240635535290b5
13a9698b6b22a23
1445a60157a52c1
151dd91b7530b0b
hexe36901734b49

250040135404361 has 2 divisors, whose sum is σ = 250040135404362. Its totient is φ = 250040135404360.

The previous prime is 250040135404229. The next prime is 250040135404387. The reversal of 250040135404361 is 163404531040052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250040089774336 + 45630025 = 15812656^2 + 6755^2 .

It is a cyclic number.

It is not a de Polignac number, because 250040135404361 - 238 = 249765257497417 is a prime.

It is not a weakly prime, because it can be changed into another prime (250040135604361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125020067702180 + 125020067702181.

It is an arithmetic number, because the mean of its divisors is an integer number (125020067702181).

Almost surely, 2250040135404361 is an apocalyptic number.

It is an amenable number.

250040135404361 is a deficient number, since it is larger than the sum of its proper divisors (1).

250040135404361 is an equidigital number, since it uses as much as digits as its factorization.

250040135404361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 38.

The spelling of 250040135404361 in words is "two hundred fifty trillion, forty billion, one hundred thirty-five million, four hundred four thousand, three hundred sixty-one".