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250040135404229 is a prime number
BaseRepresentation
bin111000110110100100000001…
…011100110100101011000101
31012210022121021221122002220012
4320312210001130310223011
5230233124144130413404
62243442504043520005
7103444542435246152
oct7066440134645305
91183277257562805
10250040135404229
11727414759a26a5
1224063553529005
13a9698b6b22951
1445a60157a5229
151dd91b7530a6e
hexe36901734ac5

250040135404229 has 2 divisors, whose sum is σ = 250040135404230. Its totient is φ = 250040135404228.

The previous prime is 250040135404151. The next prime is 250040135404361. The reversal of 250040135404229 is 922404531040052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 172675972828129 + 77364162576100 = 13140623^2 + 8795690^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250040135404229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250040135407229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125020067702114 + 125020067702115.

It is an arithmetic number, because the mean of its divisors is an integer number (125020067702115).

Almost surely, 2250040135404229 is an apocalyptic number.

It is an amenable number.

250040135404229 is a deficient number, since it is larger than the sum of its proper divisors (1).

250040135404229 is an equidigital number, since it uses as much as digits as its factorization.

250040135404229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 41.

The spelling of 250040135404229 in words is "two hundred fifty trillion, forty billion, one hundred thirty-five million, four hundred four thousand, two hundred twenty-nine".