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250042535125109 is a prime number
BaseRepresentation
bin111000110110100110010000…
…011111000010000001110101
31012210022211111012010120002022
4320312212100133002001311
5230233144102443000414
62243443542130122525
7103444656054451016
oct7066462037020165
91183284435116068
10250042535125109
11727424975344a1
1224063b03120445
13a969baa04152c
1445a61a239100d
151dd92a804e18e
hexe369907c2075

250042535125109 has 2 divisors, whose sum is σ = 250042535125110. Its totient is φ = 250042535125108.

The previous prime is 250042535125099. The next prime is 250042535125211. The reversal of 250042535125109 is 901521535240052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198137210558884 + 51905324566225 = 14076122^2 + 7204535^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250042535125109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 250042535125109.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250042535125609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125021267562554 + 125021267562555.

It is an arithmetic number, because the mean of its divisors is an integer number (125021267562555).

Almost surely, 2250042535125109 is an apocalyptic number.

It is an amenable number.

250042535125109 is a deficient number, since it is larger than the sum of its proper divisors (1).

250042535125109 is an equidigital number, since it uses as much as digits as its factorization.

250042535125109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540000, while the sum is 44.

The spelling of 250042535125109 in words is "two hundred fifty trillion, forty-two billion, five hundred thirty-five million, one hundred twenty-five thousand, one hundred nine".