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250042535134391 is a prime number
BaseRepresentation
bin111000110110100110010000…
…011111000100010010110111
31012210022211111012011000211002
4320312212100133010102313
5230233144102443300031
62243443542130233515
7103444656054520046
oct7066462037042267
91183284435130732
10250042535134391
117274249754046a
1224063b0312589b
13a969baa04581c
1445a61a239455d
151dd92a8051ccb
hexe369907c44b7

250042535134391 has 2 divisors, whose sum is σ = 250042535134392. Its totient is φ = 250042535134390.

The previous prime is 250042535134319. The next prime is 250042535134417. The reversal of 250042535134391 is 193431535240052.

250042535134391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (250042535134319) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 250042535134391 - 226 = 250042468025527 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250042535136391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125021267567195 + 125021267567196.

It is an arithmetic number, because the mean of its divisors is an integer number (125021267567196).

Almost surely, 2250042535134391 is an apocalyptic number.

250042535134391 is a deficient number, since it is larger than the sum of its proper divisors (1).

250042535134391 is an equidigital number, since it uses as much as digits as its factorization.

250042535134391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 250042535134391 in words is "two hundred fifty trillion, forty-two billion, five hundred thirty-five million, one hundred thirty-four thousand, three hundred ninety-one".