Base | Representation |
---|---|
bin | 111000110110100110010000… |
… | …011111000100010010110111 |
3 | 1012210022211111012011000211002 |
4 | 320312212100133010102313 |
5 | 230233144102443300031 |
6 | 2243443542130233515 |
7 | 103444656054520046 |
oct | 7066462037042267 |
9 | 1183284435130732 |
10 | 250042535134391 |
11 | 7274249754046a |
12 | 24063b0312589b |
13 | a969baa04581c |
14 | 45a61a239455d |
15 | 1dd92a8051ccb |
hex | e369907c44b7 |
250042535134391 has 2 divisors, whose sum is σ = 250042535134392. Its totient is φ = 250042535134390.
The previous prime is 250042535134319. The next prime is 250042535134417. The reversal of 250042535134391 is 193431535240052.
250042535134391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (250042535134319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 250042535134391 - 226 = 250042468025527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (250042535136391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125021267567195 + 125021267567196.
It is an arithmetic number, because the mean of its divisors is an integer number (125021267567196).
Almost surely, 2250042535134391 is an apocalyptic number.
250042535134391 is a deficient number, since it is larger than the sum of its proper divisors (1).
250042535134391 is an equidigital number, since it uses as much as digits as its factorization.
250042535134391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 47.
The spelling of 250042535134391 in words is "two hundred fifty trillion, forty-two billion, five hundred thirty-five million, one hundred thirty-four thousand, three hundred ninety-one".
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