25009554013 has 4 divisors (see below), whose sum is σ = 25009877088. Its totient is φ = 25009230940.

The previous prime is 25009553983. The next prime is 25009554019. The reversal of 25009554013 is 31045590052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 25009554013 - 2²¹ = 25007456861 is a prime.

It is a super-4 number, since 4×25009554013⁴ (a number of 43 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25009554013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25009554019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31368 + ... + 225838.

It is an arithmetic number, because the mean of its divisors is an integer number (6252469272).

Almost surely, 2^25009554013 is an apocalyptic number.

It is an amenable number.

25009554013 is a deficient number, since it is larger than the sum of its proper divisors (323075).

25009554013 is a wasteful number, since it uses less digits than its factorization.

25009554013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323074.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 25009554013 in words is "twenty-five billion, nine million, five hundred fifty-four thousand, thirteen".