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25012010013 = 38337336671
BaseRepresentation
bin10111010010110101…
…001111110000011101
32101120010111202110020
4113102311033300131
5402211033310023
615253530102353
71543551401664
oct272265176035
971503452406
1025012010013
11a67569a361
124a2057a9b9
132487b7cc33
1412d3bd1ddb
159b5c95de3
hex5d2d4fc1d

25012010013 has 4 divisors (see below), whose sum is σ = 33349346688. Its totient is φ = 16674673340.

The previous prime is 25012010003. The next prime is 25012010059. The reversal of 25012010013 is 31001021052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25012010013 - 212 = 25012005917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25012009974 and 25012010001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25012010003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4168668333 + ... + 4168668338.

It is an arithmetic number, because the mean of its divisors is an integer number (8337336672).

Almost surely, 225012010013 is an apocalyptic number.

It is an amenable number.

25012010013 is a deficient number, since it is larger than the sum of its proper divisors (8337336675).

25012010013 is an equidigital number, since it uses as much as digits as its factorization.

25012010013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8337336674.

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 25012010013 its reverse (31001021052), we get a palindrome (56013031065).

The spelling of 25012010013 in words is "twenty-five billion, twelve million, ten thousand, thirteen".

Divisors: 1 3 8337336671 25012010013