Base | Representation |
---|---|
bin | 10111010100011111… |
… | …111000011111101111 |
3 | 2101122002002222022101 |
4 | 113110133320133233 |
5 | 402240212323033 |
6 | 15300405155531 |
7 | 1544341116625 |
oct | 272437703757 |
9 | 71562088271 |
10 | 25039964143 |
11 | a68a452747 |
12 | 4a299bbba7 |
13 | 24908b993c |
14 | 12d77cb515 |
15 | 9b846897d |
hex | 5d47f87ef |
25039964143 has 2 divisors, whose sum is σ = 25039964144. Its totient is φ = 25039964142.
The previous prime is 25039964123. The next prime is 25039964161. The reversal of 25039964143 is 34146993052.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25039964143 - 221 = 25037866991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25039964093 and 25039964102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25039964123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12519982071 + 12519982072.
It is an arithmetic number, because the mean of its divisors is an integer number (12519982072).
Almost surely, 225039964143 is an apocalyptic number.
25039964143 is a deficient number, since it is larger than the sum of its proper divisors (1).
25039964143 is an equidigital number, since it uses as much as digits as its factorization.
25039964143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 699840, while the sum is 46.
The spelling of 25039964143 in words is "twenty-five billion, thirty-nine million, nine hundred sixty-four thousand, one hundred forty-three".
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