Base | Representation |
---|---|
bin | 100100011100001011001… |
… | …010111000011001110101 |
3 | 22212101122202021212022010 |
4 | 210130023022320121311 |
5 | 312012001223213123 |
6 | 5154220412354433 |
7 | 345630153102132 |
oct | 44341312703165 |
9 | 8771582255263 |
10 | 2504153335413 |
11 | 886007302694 |
12 | 3453a3a75a19 |
13 | 1521a9ccc962 |
14 | 892b753d589 |
15 | 45213573993 |
hex | 2470b2b8675 |
2504153335413 has 8 divisors (see below), whose sum is σ = 3338912727808. Its totient is φ = 1669414749984.
The previous prime is 2504153335351. The next prime is 2504153335417. The reversal of 2504153335413 is 3145333514052.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2504153335413 - 229 = 2503616464501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2504153335417) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4918720 + ... + 5403897.
It is an arithmetic number, because the mean of its divisors is an integer number (417364090976).
Almost surely, 22504153335413 is an apocalyptic number.
It is an amenable number.
2504153335413 is a deficient number, since it is larger than the sum of its proper divisors (834759392395).
2504153335413 is a wasteful number, since it uses less digits than its factorization.
2504153335413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10403483.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 2504153335413 its reverse (3145333514052), we get a palindrome (5649486849465).
The spelling of 2504153335413 in words is "two trillion, five hundred four billion, one hundred fifty-three million, three hundred thirty-five thousand, four hundred thirteen".
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