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250514119999981 is a prime number
BaseRepresentation
bin111000111101011101011101…
…001000100100000111101101
31012211222220201202021100120001
4320331131131020210013231
5230313410404204444411
62244444333054424301
7103524022266655105
oct7075353510440755
91184886652240501
10250514119999981
1172904494939902
122411b393b02091
13a9a24c32656a6
1445c0d3b844205
151de66a926adc1
hexe3d75d2241ed

250514119999981 has 2 divisors, whose sum is σ = 250514119999982. Its totient is φ = 250514119999980.

The previous prime is 250514119999811. The next prime is 250514120000057. The reversal of 250514119999981 is 189999911415052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 168734020734756 + 81780099265225 = 12989766^2 + 9043235^2 .

It is a cyclic number.

It is not a de Polignac number, because 250514119999981 - 29 = 250514119999469 is a prime.

It is a super-2 number, since 2×2505141199999812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250514129999981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125257059999990 + 125257059999991.

It is an arithmetic number, because the mean of its divisors is an integer number (125257059999991).

Almost surely, 2250514119999981 is an apocalyptic number.

It is an amenable number.

250514119999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

250514119999981 is an equidigital number, since it uses as much as digits as its factorization.

250514119999981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94478400, while the sum is 73.

The spelling of 250514119999981 in words is "two hundred fifty trillion, five hundred fourteen billion, one hundred nineteen million, nine hundred ninety-nine thousand, nine hundred eighty-one".