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25054554413543 is a prime number
BaseRepresentation
bin1011011001001011101111…
…10100001101100111100111
310021201012011222022222112212
411230211313310031213213
511240443211412213133
6125141523045034035
75164063133446304
oct554456764154747
9107635158288485
1025054554413543
117a8a638882986
1229878a76b591b
1310c9832863775
1462890b1660ab
152d6ad6bd8148
hex16c977d0d9e7

25054554413543 has 2 divisors, whose sum is σ = 25054554413544. Its totient is φ = 25054554413542.

The previous prime is 25054554413513. The next prime is 25054554413569. The reversal of 25054554413543 is 34531445545052.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25054554413543 - 222 = 25054550219239 is a prime.

It is a super-2 number, since 2×250545544135432 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25054554413491 and 25054554413500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25054554413513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12527277206771 + 12527277206772.

It is an arithmetic number, because the mean of its divisors is an integer number (12527277206772).

Almost surely, 225054554413543 is an apocalyptic number.

25054554413543 is a deficient number, since it is larger than the sum of its proper divisors (1).

25054554413543 is an equidigital number, since it uses as much as digits as its factorization.

25054554413543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400000, while the sum is 50.

Adding to 25054554413543 its reverse (34531445545052), we get a palindrome (59585999958595).

The spelling of 25054554413543 in words is "twenty-five trillion, fifty-four billion, five hundred fifty-four million, four hundred thirteen thousand, five hundred forty-three".