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2510241239113 is a prime number
BaseRepresentation
bin100100100001110110000…
…010011001000001001001
322212222101000202102011221
4210201312002121001021
5312111433224122423
65201104445322041
7346234055322406
oct44416602310111
98788330672157
102510241239113
11888650812863
12346602866321
1315293a36543a
14896d3cb12ad
154546cc71e5d
hex24876099049

2510241239113 has 2 divisors, whose sum is σ = 2510241239114. Its totient is φ = 2510241239112.

The previous prime is 2510241239111. The next prime is 2510241239123. The reversal of 2510241239113 is 3119321420152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1904253722809 + 605987516304 = 1379947^2 + 778452^2 .

It is a cyclic number.

It is not a de Polignac number, because 2510241239113 - 21 = 2510241239111 is a prime.

It is a super-2 number, since 2×25102412391132 (a number of 26 digits) contains 22 as substring.

Together with 2510241239111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2510241239111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1255120619556 + 1255120619557.

It is an arithmetic number, because the mean of its divisors is an integer number (1255120619557).

Almost surely, 22510241239113 is an apocalyptic number.

It is an amenable number.

2510241239113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2510241239113 is an equidigital number, since it uses as much as digits as its factorization.

2510241239113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

Adding to 2510241239113 its reverse (3119321420152), we get a palindrome (5629562659265).

The spelling of 2510241239113 in words is "two trillion, five hundred ten billion, two hundred forty-one million, two hundred thirty-nine thousand, one hundred thirteen".