Base | Representation |
---|---|
bin | 100100100001110110001… |
… | …110000111100000101010 |
3 | 22212222101020112120221102 |
4 | 210201312032013200222 |
5 | 312111440021010010 |
6 | 5201105035241402 |
7 | 346234123414511 |
oct | 44416616074052 |
9 | 8788336476842 |
10 | 2510244313130 |
11 | 888652522374 |
12 | 3466038a9262 |
13 | 15293aba0698 |
14 | 896d4471678 |
15 | 4546d17cba5 |
hex | 2487638782a |
2510244313130 has 16 divisors (see below), whose sum is σ = 4575635205120. Its totient is φ = 991387627152.
The previous prime is 2510244313123. The next prime is 2510244313151. The reversal of 2510244313130 is 313134420152.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2510244313093 and 2510244313102.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1588761434 + ... + 1588763013.
It is an arithmetic number, because the mean of its divisors is an integer number (285977200320).
Almost surely, 22510244313130 is an apocalyptic number.
2510244313130 is a deficient number, since it is larger than the sum of its proper divisors (2065390891990).
2510244313130 is a wasteful number, since it uses less digits than its factorization.
2510244313130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3177524533.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 2510244313130 its reverse (313134420152), we get a palindrome (2823378733282).
The spelling of 2510244313130 in words is "two trillion, five hundred ten billion, two hundred forty-four million, three hundred thirteen thousand, one hundred thirty".
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