25104113 has 2 divisors, whose sum is σ = 25104114. Its totient is φ = 25104112.

The previous prime is 25104103. The next prime is 25104127. The reversal of 25104113 is 31140152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16056049 + 9048064 = 4007^2 + 3008^2 .

It is a cyclic number.

It is not a de Polignac number, because 25104113 - 2¹² = 25100017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25104091 and 25104100.

It is not a weakly prime, because it can be changed into another prime (25104103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12552056 + 12552057.

It is an arithmetic number, because the mean of its divisors is an integer number (12552057).

Almost surely, 2^25104113 is an apocalyptic number.

It is an amenable number.

25104113 is a deficient number, since it is larger than the sum of its proper divisors (1).

25104113 is an equidigital number, since it uses as much as digits as its factorization.

25104113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 25104113 is about 5010.4004829953. The cubic root of 25104113 is about 292.8071160008.

Adding to 25104113 its reverse (31140152), we get a palindrome (56244265).

The spelling of 25104113 in words is "twenty-five million, one hundred four thousand, one hundred thirteen".