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25104454117 is a prime number
BaseRepresentation
bin10111011000010101…
…111001000111100101
32101210120110101220221
4113120111321013211
5402403220012432
615311031324341
71546053224221
oct273025710745
971716411827
1025104454117
11a71289aa46
124a475206b1
1324a10794a2
1413021b7781
159bde56b97
hex5d85791e5

25104454117 has 2 divisors, whose sum is σ = 25104454118. Its totient is φ = 25104454116.

The previous prime is 25104454103. The next prime is 25104454147. The reversal of 25104454117 is 71145440152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13867182081 + 11237272036 = 117759^2 + 106006^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25104454117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25104454147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12552227058 + 12552227059.

It is an arithmetic number, because the mean of its divisors is an integer number (12552227059).

Almost surely, 225104454117 is an apocalyptic number.

It is an amenable number.

25104454117 is a deficient number, since it is larger than the sum of its proper divisors (1).

25104454117 is an equidigital number, since it uses as much as digits as its factorization.

25104454117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22400, while the sum is 34.

Adding to 25104454117 its reverse (71145440152), we get a palindrome (96249894269).

The spelling of 25104454117 in words is "twenty-five billion, one hundred four million, four hundred fifty-four thousand, one hundred seventeen".