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25105331422141 is a prime number
BaseRepresentation
bin1011011010101010010100…
…10111001000001110111101
310021220001020201020021120221
411231111022113020032331
511242311204321002031
6125221121404341341
75200541342060245
oct555251227101675
9107801221207527
1025105331422141
117aaa125102aa3
1229956b8844851
131101565596499
1462b166b58b25
152d80a98b2a11
hex16d54a5c83bd

25105331422141 has 2 divisors, whose sum is σ = 25105331422142. Its totient is φ = 25105331422140.

The previous prime is 25105331422057. The next prime is 25105331422163. The reversal of 25105331422141 is 14122413350152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22986472725241 + 2118858696900 = 4794421^2 + 1455630^2 .

It is a cyclic number.

It is not a de Polignac number, because 25105331422141 - 211 = 25105331420093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25105331422097 and 25105331422106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25105331423141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12552665711070 + 12552665711071.

It is an arithmetic number, because the mean of its divisors is an integer number (12552665711071).

Almost surely, 225105331422141 is an apocalyptic number.

It is an amenable number.

25105331422141 is a deficient number, since it is larger than the sum of its proper divisors (1).

25105331422141 is an equidigital number, since it uses as much as digits as its factorization.

25105331422141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 25105331422141 its reverse (14122413350152), we get a palindrome (39227744772293).

The spelling of 25105331422141 in words is "twenty-five trillion, one hundred five billion, three hundred thirty-one million, four hundred twenty-two thousand, one hundred forty-one".