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251121133561 is a prime number
BaseRepresentation
bin1110100111011111111…
…1000110011111111001
3220000012001201100020111
43221313333012133321
513103244002233221
6311210301224321
724100005262504
oct3516777063771
9800161640214
10251121133561
1197555373511
1240803b620a1
131a8b042bc2c
14c22369213b
1567eb476be1
hex3a77fc67f9

251121133561 has 2 divisors, whose sum is σ = 251121133562. Its totient is φ = 251121133560.

The previous prime is 251121133559. The next prime is 251121133639. The reversal of 251121133561 is 165331121152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 249300490000 + 1820643561 = 499300^2 + 42669^2 .

It is a cyclic number.

It is not a de Polignac number, because 251121133561 - 21 = 251121133559 is a prime.

It is a super-4 number, since 4×2511211335614 (a number of 47 digits) contains 4444 as substring.

Together with 251121133559, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (251121131561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125560566780 + 125560566781.

It is an arithmetic number, because the mean of its divisors is an integer number (125560566781).

Almost surely, 2251121133561 is an apocalyptic number.

It is an amenable number.

251121133561 is a deficient number, since it is larger than the sum of its proper divisors (1).

251121133561 is an equidigital number, since it uses as much as digits as its factorization.

251121133561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 31.

The spelling of 251121133561 in words is "two hundred fifty-one billion, one hundred twenty-one million, one hundred thirty-three thousand, five hundred sixty-one".