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25113050033 is a prime number
BaseRepresentation
bin10111011000110110…
…101011101110110001
32101211011122010022012
4113120312223232301
5402412420100113
615311535452305
71546216255211
oct273066535661
971734563265
1025113050033
11a717731205
124a4a387095
1324a2a98c26
1413033b4241
159beaa3aa8
hex5d8dabbb1

25113050033 has 2 divisors, whose sum is σ = 25113050034. Its totient is φ = 25113050032.

The previous prime is 25113050021. The next prime is 25113050057. The reversal of 25113050033 is 33005031152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14336949169 + 10776100864 = 119737^2 + 103808^2 .

It is a cyclic number.

It is not a de Polignac number, because 25113050033 - 220 = 25112001457 is a prime.

It is a super-2 number, since 2×251130500332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25113049990 and 25113050008.

It is not a weakly prime, because it can be changed into another prime (25113050933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12556525016 + 12556525017.

It is an arithmetic number, because the mean of its divisors is an integer number (12556525017).

Almost surely, 225113050033 is an apocalyptic number.

It is an amenable number.

25113050033 is a deficient number, since it is larger than the sum of its proper divisors (1).

25113050033 is an equidigital number, since it uses as much as digits as its factorization.

25113050033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 23.

Adding to 25113050033 its reverse (33005031152), we get a palindrome (58118081185).

The spelling of 25113050033 in words is "twenty-five billion, one hundred thirteen million, fifty thousand, thirty-three".