25114050041 has 4 divisors (see below), whose sum is σ = 25294726800. Its totient is φ = 24933373284.

The previous prime is 25114050029. The next prime is 25114050113. The reversal of 25114050041 is 14005041152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25114050041 - 2³⁰ = 24040308217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25114049989 and 25114050016.

It is not an unprimeable number, because it can be changed into a prime (25114050001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90338171 + ... + 90338448.

It is an arithmetic number, because the mean of its divisors is an integer number (6323681700).

Almost surely, 2^25114050041 is an apocalyptic number.

It is an amenable number.

25114050041 is a deficient number, since it is larger than the sum of its proper divisors (180676759).

25114050041 is a wasteful number, since it uses less digits than its factorization.

25114050041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 180676758.

The product of its (nonzero) digits is 800, while the sum is 23.

Adding to 25114050041 its reverse (14005041152), we get a palindrome (39119091193).

The spelling of 25114050041 in words is "twenty-five billion, one hundred fourteen million, fifty thousand, forty-one".